While what I have said earlier is true, it doesn't stop the fact that using
positive values should give a correct answer, if not a complete one.
After all, (4 - 9/2)^2 = (5 - 9/2)^2
is still true as both sides are equal to another.
Much like (1 - 2)^2 = (3 - 2)^2 and yet, if you square root both sides,
1 - 2 = 3 - 2
or 1 = 3
Clearly not true. This is because while you can square two sides to achieve the same answer, after your equation has become quadratic (you squared it, and now it has more than one solution) then you can't really attempt to prove your original equation backwards by square rooting both sides. Square rooting a quadratic equation always gives more than one answer.
so, +-sqrt(1 - 2)^2 = +-sqrt(3 - 2)^2
the answer is +-(1 - 2) = +-(3 - 2)
which gives, for +, -1 = +1 or +1 = -1....thus, the solution to this quadratic equation (by square rooting both sides) is +1, -1 (you cannot separate the -2s by adding 2 to each side). Note that the difference between the solutions +1 and -1 is equal to 2. Looking back to 1 = 3, 2 is exactly what differentiates them.
Going back to your equation, (4 - 9/2)^2 = (5 - 9/2)^2.
That should be the same as +-(4 - 9/2) = +-(5 - 9/2)
so, for + values, -1/2 = +1/2 and for - values, +1/2 = -1/2. The two solutions to your quadratic equation are +1/2, -1/2. The difference between each solution is 1. Looking back to 4 = 5, 1 is exactly what differentiates them.
So, my point? You cannot prove a single-solution equation by working backwards from a quadratic equation.
eg: 3 = 3..........3^2 = 3^2.........9 = 9
But sqrt(9) = +-3 (so you can't prove your first equation 3 = 3 by going backwards). But even so, there are ways to make sense out of it. In the meantime, I'm going to need a headache pill myself.